我有13255个图像,每个240 x 240像素宽,最大的15,412字节大小和最小的839字节.
我试图循环文件夹将每个文件添加到File [].一旦我有一个每个图像的数组,然后我将它们放在BufferedImage []中,准备好循环并绘制到由每个图像组成的更大的单个图像上.
每个图像都以.的形式命名
Image x-y.png
但是,我一直以java.lang.OutOfMemoryError:Java堆空间错误结束.我不知道为什么.我已经尝试通过向Eclipse的目标末尾添加参数来更改JVM可用内存的大小.以下是我用过的内容:
IDE's\eclipse-jee-juno-SR2-win32-x86_64\eclipse\eclipse.exe -vmargs -Xms64m -Xmx1024m
和
IDE's\eclipse-jee-juno-SR2-win32-x86_64\eclipse\eclipse.exe -vmargs -Xms64m -Xmx4096m
两者都没有效果.我也进入了控制面板 – >程序 – > Java并改变了那里可用的内存量.
这是我写的方法:
public static void merge_images() throws IOException {
int rows = 115;
int cols = 115;
int chunks = rows * cols;
System.out.println(chunks);
int chunkWidth, chunkHeight;
int type;
// fetching image files
File[] imgFiles = new File[chunks];
int count = 0;
for (int j = 1; j <= 115; j++) {
for (int k = 1; k <= 115; k++) {
imgFiles[count] = new File("G:\\Images\\Image " + j
+ "-" + k + ".png");
count++;
}
}
System.out.println(imgFiles.length);
// creating a buffered image array from image files
BufferedImage[] buffImages = new BufferedImage[chunks];
for (int i = 0; i < chunks; i++) {
buffImages[i] = ImageIO.read(imgFiles[i]);
System.out.println(i);
}
type = buffImages[0].getType();
chunkWidth = buffImages[0].getWidth();
chunkHeight = buffImages[0].getHeight();
// Initializing the final image
BufferedImage finalImg = new BufferedImage(chunkWidth * cols,
chunkHeight * rows, type);
int num = 0;
for (int i = 0; i < rows; i++) {
for (int k = 0; k < cols; k++) {
finalImg.createGraphics().drawImage(buffImages[num], null,
chunkWidth * k, chunkHeight * i);
num++;
}
}
System.out.println("Image concatenated.....");
ImageIO.write(finalImg, "png", new File("fusions.png"));
System.out.println("Image Saved, Exiting");
}
在这里的打印线
for (int i = 0; i < chunks; i++) {
buffImages[i] = ImageIO.read(imgFiles[i]);
System.out.println(i);
}
它总是停在7320点左右.
这是确切的控制台打印输出
Exception in thread "main" java.lang.OutOfMemoryError: Java heap space
at java.awt.image.DataBufferByte.<init>(Unknown Source)
at java.awt.image.ComponentSampleModel.createDataBuffer(Unknown Source)
at java.awt.image.Raster.createWritableRaster(Unknown Source)
at javax.imageio.ImageTypeSpecifier.createBufferedImage(Unknown Source)
at javax.imageio.ImageReader.getDestination(Unknown Source)
at com.sun.imageio.plugins.png.PNGImageReader.readImage(Unknown Source)
at com.sun.imageio.plugins.png.PNGImageReader.read(Unknown Source)
at javax.imageio.ImageIO.read(Unknown Source)
at javax.imageio.ImageIO.read(Unknown Source)
at main.merge_images(main.java:48)
at main.main(main.java:19)
任何我出错的想法都将不胜感激.
问候,
杰米
解决方法:
您不需要将所有块图像保留在内存中.您可以逐个阅读它们并在最终循环中绘制到最终图像,如下所示:
for (int i = 0; i < rows; i++) {
for (int k = 0; k < cols; k++) {
BufferedImage buffImage = ImageIO.read(imgFiles[num]);
finalImg.createGraphics().drawImage(buffImage, null,
chunkWidth * k, chunkHeight * i);
num++;
}
}
这将节省至少一半的内存.