在JavaScript中从ArrayBuffer获取二进制字符串的方法是什么?
我不想编码字节,只是将二进制表示形式为String.
提前致谢!
解决方法:
以下代码将始终将ArrayBuffer转换为String并再次返回,而不会丢失或添加任何其他字节.
function ArrayBufferToString(buffer) {
return BinaryToString(String.fromCharCode.apply(null, Array.prototype.slice.apply(new Uint8Array(buffer))));
}
function StringToArrayBuffer(string) {
return StringToUint8Array(string).buffer;
}
function BinaryToString(binary) {
var error;
try {
return decodeURIComponent(escape(binary));
} catch (_error) {
error = _error;
if (error instanceof URIError) {
return binary;
} else {
throw error;
}
}
}
function StringToBinary(string) {
var chars, code, i, isUCS2, len, _i;
len = string.length;
chars = [];
isUCS2 = false;
for (i = _i = 0; 0 <= len ? _i < len : _i > len; i = 0 <= len ? ++_i : --_i) {
code = String.prototype.charCodeAt.call(string, i);
if (code > 255) {
isUCS2 = true;
chars = null;
break;
} else {
chars.push(code);
}
}
if (isUCS2 === true) {
return unescape(encodeURIComponent(string));
} else {
return String.fromCharCode.apply(null, Array.prototype.slice.apply(chars));
}
}
function StringToUint8Array(string) {
var binary, binLen, buffer, chars, i, _i;
binary = StringToBinary(string);
binLen = binary.length;
buffer = new ArrayBuffer(binLen);
chars = new Uint8Array(buffer);
for (i = _i = 0; 0 <= binLen ? _i < binLen : _i > binLen; i = 0 <= binLen ? ++_i : --_i) {
chars[i] = String.prototype.charCodeAt.call(binary, i);
}
return chars;
}
我通过在这个jsfiddle:http://jsfiddle.net/potatosalad/jrdLV/中绕过以下值来测试它
(String) "abc" -> (ArrayBuffer) -> (String) "abc"
(String) "aΩc" -> (ArrayBuffer) -> (String) "aΩc"
(Uint8Array) [0,1,255] -> (ArrayBuffer) -> (String) -> (Uint8Array) [0,1,255]
(Uint16Array) [0,1,256,65535] -> (ArrayBuffer) -> (String) -> (Uint16Array) [0,1,256,65535]
(Uint32Array) [0,1,256,65536,4294967295] -> (ArrayBuffer) -> (String) -> (Uint32Array) [0,1,256,65536,4294967295]