我这里有这个linux nasm代码,不会崩溃.使用printString结尾的ret 80指令不应该这个程序崩溃？

bits 32

section .data
    hello:     db 'Hello Linux assembly!!!!!!!!!!!!!!!!!!!',10,0    
    helloLen:  equ $-hello  

    anotherString db "hello im another string!!!!",10,0
    anotherStringlen equ $-anotherString

section .text
    global _start

_start:
    push hello
    push helloLen
    call printString

;;;; should i pop the two paramters I pushed?
;;;; does the ret instruction do it for me?

    push anotherString
    push anotherStringlen
    call printString

    call exit

printString:
    push ebp
    mov ebp, esp

    mov eax, 4
    mov ebx, 1
    mov ecx, [ebp+12] 
    mov edx, [ebp+8]
    int 80h

    pop ebp
    ret 60 ;;;;; How does this not make printString crash?

exit:
    mov eax,1            
    mov ebx,0            
    int 80h

解决方法:

在汇编语言中不正确地做事并不能确保你会崩溃.

ret 60指令在返回后从堆栈中弹出错误数量的值.但是,接下来的事情并不是假设堆栈上有任何使用值.例如,退出函数不关心堆栈是否已被删除,并且仍将退出您的进程.