[LeetCode&Python] Problem 744. Find Smallest Letter Greater Than Target

Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target.

Letters also wrap around. For example, if the target is target = 'z' and letters = ['a', 'b'], the answer is 'a'.

Examples:

Input:
letters = ["c", "f", "j"]
target = "a"
Output: "c" Input:
letters = ["c", "f", "j"]
target = "c"
Output: "f" Input:
letters = ["c", "f", "j"]
target = "d"
Output: "f" Input:
letters = ["c", "f", "j"]
target = "g"
Output: "j" Input:
letters = ["c", "f", "j"]
target = "j"
Output: "c" Input:
letters = ["c", "f", "j"]
target = "k"
Output: "c"

Note:

  1. letters has a length in range [2, 10000].
  2. letters consists of lowercase letters, and contains at least 2 unique letters.
  3. target is a lowercase letter.
class Solution(object):
def nextGreatestLetter(self, letters, target):
"""
:type letters: List[str]
:type target: str
:rtype: str
"""
i=0
n=len(letters)
o=ord(target)
while i<n:
if ord(letters[i])>o:
return letters[i]
else:
i+=1
if i==n:
return letters[0]

  

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