最近在提高自己编程能力,拿一些实用的小工具练下。该脚本为python语言,主要涉及模块urllib,json,os模块。
功能:调用ZoomEye API获取信息
import urllib.request
import json
import os def login():
username = input("username:")
password = input("password:")
url = "https://api.zoomeye.org/user/login"
data = json.dumps({'username':username,'password':password})
data_bytes = bytes(data,'utf8')
try:
req = urllib.request.Request(url,data_bytes)
response = urllib.request.urlopen(req)
html = response.read().decode('utf-8')
target = json.loads(html) access_token = target['access_token']
with open('access_token.txt','w') as f:
f.write(access_token)
f.close
print('login seccess !!!')
#print('your access_token is:%s'%(access_token))
except Exception as err:
print('[info]:username or password is wrong !') def apiget():
while True:
host_or_web = input("search for host or web:(‘q!’Sign out):")
if host_or_web == 'q!':
break
query = input("input your keyword(-r for your resources-info):") #查看自己的套餐剩余量
if query == '-r':
req = urllib.request.Request('https://api.zoomeye.org/resources-info')
ida = open('access_token.txt').read() req.add_header('Authorization','JWT %s'%(ida))
re = urllib.request.urlopen(req)
ae = (re.read().decode('utf-8'))
ae = target = json.loads(ae)
dict_web = ae['resources']['web-search']
dict_host = ae['resources']['host-search']
print('your web search:%s'%(dict_web))
print('your host search:%s'%(dict_host))
else:
try:
req = urllib.request.Request('https://api.zoomeye.org/%s/search?query=%s'%(host_or_web,query))
idb = open('access_token.txt').read()
req.add_header('Authorization','JWT %s'%(idb))
r = urllib.request.urlopen(req)
a = (r.read().decode('utf-8'))
a = target = json.loads(a)
print('tatal:%s'%(a['total']))
for i in range(len(a['matches'])):
print (a['matches'][i]['ip']) except Exception as err:
print('[erro]:Please enter the correct syntax !') def start():
if not os.path.isfile('access_token.txt'): #首次使用会检查脚本目录下access_token.txt文件,没有的话登录会创建
print('[info]:you need login')
login() apiget() if __name__ == '__main__':
start()