题目:给定一个链表L和另一个链表P,它们包含以升序排列的整数。操作printLots打印L中那些由P所指定的位置上的元素。写出过程printLots(L,P)。只可以使用公有的STL容器操作。该过程的运行时间是多少?
我编写的程序如下:
#include <iostream> using namespace std; template <typename Object>
class List
{
private:
struct Node //List内部维护的节点类
{
Object data;
Node *prev;
Node *next; Node( const Object &d = Object(),Node *p = NULL,Node *n = NULL )
: data( d ),prev( p ),next( n ) { }
}; public:
class const_iterator //常量迭代器
{
public:
const_iterator() : current( NULL )
{ } const Object &operator*() const
{ return retrieve(); } const_iterator &operator++()
{
current = current->next;
return *this;
} const_iterator operator++( int )
{
const_iterator old = *this;
++( *this );
return old;
} bool operator== ( const const_iterator &rhs ) const
{ return current == rhs.current; } bool operator!= ( const const_iterator &rhs ) const
{ return !( *this == rhs ); } protected:
Node *current; Object &retrieve() const
{ return current->data; } const_iterator( Node *p ) : current( p )
{ } friend class List<Object>;
}; class iterator : public const_iterator //迭代器类继承自常量迭代器类
{
public:
iterator()
{ } Object &operator*()
{ return const_iterator::retrieve(); } const Object &operator*() const
{ return const_iterator::operator*(); } iterator &operator++()
{
const_iterator::current = const_iterator::current->next;
return *this;
} iterator operator++( int )
{
iterator old = *this;
++( *this ); return old;
} protected:
iterator( Node *p ) : const_iterator( p )
{ } friend class List<Object>;
}; public:
List()
{ init(); } ~List()
{
clear();
delete head;
delete tail;
} List( const List &rhs )
{
init();
*this = rhs;
} const List &operator= ( const List &rhs )
{
if ( this == &rhs )
return *this;
clear();
for ( const_iterator itr = rhs.begin() ; itr != rhs.end() ; ++itr )
push_back( *itr ); return *this;
} iterator begin()
{ return iterator( head->next ); }
const_iterator begin() const
{ return const_iterator( head->next ); }
iterator end()
{ return iterator( tail ); }
const_iterator end() const
{ return const_iterator( tail ); } int size() const
{ return theSize; }
bool empty() const
{ return size() == ; } void clear()
{
while ( !empty() )
pop_front();
} Object &front()
{ return *begin(); }
const Object &front() const
{ return *begin(); }
Object &back()
{ return *--end(); }
const Object &back() const
{ return *--end(); }
void push_front( const Object &x )
{ insert( begin(),x ); }
void push_back( const Object &x )
{ insert( end(),x ); }
void pop_front()
{ erase( begin() ); }
void pop_back()
{ erase( --end() ); } iterator insert( iterator itr,const Object &x )
{
Node *p = itr.current;
theSize++;
return ( p->prev = p->prev->next = new Node( x,p->prev,p ) );
} iterator erase( iterator itr )
{
Node *p = itr.current;
iterator retVal( p->next );
p->prev->next = p->next;
p->next->prev = p->prev;
delete p;
theSize--; return retVal;
} iterator erase( iterator start,iterator end )
{
for ( iterator itr = start ; itr != end; )
itr = erase( itr ); return end;
} private:
int theSize;
Node *head;
Node *tail; void init()
{
theSize = ;
head = new Node;
tail = new Node;
head->next = tail;
tail->prev = head;
}
}; void printLots( List<int> &L,List<int> &P ) //打印出L链表 指定位置(P中存放)的值
{
List<int>::const_iterator itr = L.begin();
int count = ; //P是升序排列那么不必每次遍历L,维护计数器一直递增迭代器即可 for ( List<int>::const_iterator itr_P = P.begin() ; itr_P != P.end() ; ++itr_P ){
int pos = *itr_P;
while ( pos != count ){
if ( itr == L.end() )
return ;
count++;
itr++;
}
if ( itr != L.end() )
cout << *itr << endl;
} return ;
} int main( void )
{
List<int> p,temp;
p.push_back( );
p.push_back( ); temp.push_back( );
temp.push_back( ); cout << "The pos List:" << endl; for ( List<int>::iterator iter = p.begin() ; iter != p.end() ; ++iter )
cout << *iter << " "; cout << endl; cout << "The temp List:" << endl;
printLots( temp,p ); return ;
}
运行结果:
printLots过程中temp链表迭代P中的最大值 次,所以运行时间是取决于P中最后一个元素N,O(N)。