import re

 # 正则表达式，|元字符表示选择“或”

 # character = 'bat|bit|but|hat|hit|hut' # 方法一

 # character = '[bh][aiu]t'  # 方法二

 character = '(b|h)(a|i|u)t' # 方法三

 # 测试数据

 data = 'bat'

 data1 = 'bit'

 data2 = 'but'

 data3 = 'hat'

 data4 = 'hit'

 data5 = 'hut'

 # 测试开始

 m = re.match(character, data)

 m1 = re.match(character, data1)

 m2 = re.match(character, data2)

 m3 = re.match(character, data3)

 m4 = re.match(character, data4)

 m5 = re.match(character, data5)

 if m is not None:

     print("data与character匹配成功，结果为:")

     print(m.group())

 if m1 is not None:

     print("data1与character匹配成功，结果为:")

     print(m1.group())

 if m2 is not None:

     print("data2与character匹配成功，结果为:")

     print(m2.group())

 if m3 is not None:

     print("data3与character匹配成功，结果为:")

     print(m3.group())

 if m4 is not None:

     print("data4与character匹配成功，结果为:")

     print(m4.group())

 if m5 is not None:

     print("data5与character匹配成功，结果为:")

     print(m5.group())