我的网址是：

example.com/controller/function/parameter
=> example.com/category/index/category_name

我需要：

example.com/category/category_name

我已经尝试过*提供的几种解决方案,但是对此却无法解决.它要么重定向到主页,要么找不到404页面.

我尝试过的选项是：

$route['category'] = "category/index"; //1

$route['category/(:any)'] = "category/index"; //2

$route['category/(:any)'] = "category/index/$1";  //3

另一条路线是：

$route['default_controller'] = 'home';

htaccess文件：

RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond $1 !^(index\.php|images|robots\.txt|css)
RewriteRule ^(.*)$index.php/$1 [L]

在配置文件中,我有：

$config['url_suffix'] = '';

解决方法:

我认为您的.htaccess文件中有错误.请在下面找到.htaccess文件的代码.

您可以使用RewriteBase为您的重写提供基础.

RewriteEngine On
RewriteBase /campnew/
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond $1 !^(index\.php|images|robots\.txt|css)
RewriteRule ^(.*)$index.php/$1 [L]

在Controller中,您的方法.

public function index($category_name = null) {
    $this->load->model('category_model');

    $data = array();

    if ($query = $this->category_model->get_records_view($category_name)) {
        $data['recordss'] = $query;
    }
    if ($query2 = $this->category_model->get_records_view2($category_name)) 
    {
        $data['recordsc2'] = $query2;
    }

    $data['main_content'] = 'category';
    $this->load->view('includes/template', $data);
}

在模型文件中

public function get_records_view($category){
    $this->db->where('a.linkname', $category); 
}

让我知道是否有效.