Can you find it?
Time Limit: 10000/3000 MS (Java/Others) Memory Limit: 32768/10000 K (Java/Others)
Total Submission(s): 19416 Accepted Submission(s): 4891
Problem Description
Give you three sequences of numbers A, B, C, then we give you a number X. Now you need to calculate if you can find the three numbers Ai, Bj, Ck, which satisfy the formula Ai+Bj+Ck = X.
Input
There are many cases. Every data case is described as followed: In the first line there are three integers L, N, M, in the second line there are L integers represent the sequence A, in the third line there are N integers represent the sequences B, in the forth line there are M integers represent the sequence C. In the fifth line there is an integer S represents there are S integers X to be calculated. 1<=L, N, M<=500, 1<=S<=1000. all the integers are 32-integers.
Output
For each case, firstly you have to print the case number as the form "Case d:", then for the S queries, you calculate if the formula can be satisfied or not. If satisfied, you print "YES", otherwise print "NO".
Sample Input
3 3 3
1 2 3
1 2 3
1 2 3
3
1
4
10
1 2 3
1 2 3
1 2 3
3
1
4
10
Sample Output
Case 1:
NO
YES
NO
lower_bound提交就会出错，binary_search()也可以过
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <set>
using namespace std;
int a[],b[],c[],x;
__int64 su[*];
int l,n,m,s,u;
int d=,sum;
bool solve(int x)
{
int i,k;
int ans;
for(i=;i<m;i++)
{
ans=x-c[i];
int l=,r=u-,mid,e;
while(l<=r)
{
mid=(l+r)/;
if(su[mid]==ans) return ;
else if(su[mid]>ans) r=mid-;
else l=mid+;
}
}
return ;
}
int main()
{
int i,j;
freopen("in.txt","r",stdin);
while(scanf("%d%d%d",&l,&n,&m)!=EOF)
{
for(i=;i<l;i++) scanf("%d",&a[i]);
for(i=;i<n;i++) scanf("%d",&b[i]);
for(i=;i<m;i++) scanf("%d",&c[i]);
scanf("%d",&s);
u=;
for(i=;i<l;i++)
for(j=;j<n;j++)
su[u++]=a[i]+b[j];
sort(su,su+u);
printf("Case %d:\n",d++);
for(i=;i<s;i++)
{
scanf("%d",&x);
if(solve(x)) printf("YES\n");
else printf("NO\n");
}
}
}