使用贴现率8%和12%分别计算每个项目的净现值(NPV)  JAVA实现

 

 

净现值求解

 

 

 

实现代码（JAVA）：

package com.zuoye.Three;

import java.math.BigDecimal;

public class TieXianLu {

    public static void main(String[] args) throws Exception {
        //数据集合
        int[] math1 = new int[]{-100000, 10000, 10000, 10000, 20000, 100000};
        int[] math2 = new int[]{-1000000, 200000, 200000, 200000, 200000,300000};
        int[] math3 = new int[]{-100000, 30000, 30000, 30000, 30000, 30000};
        int[] math4 = new int[]{-120000, 30000, 30000, 30000, 30000, 75000};

        //贴现率
        double [] txl = new double[] {0.08,0.12};
        double[][] b=new double[2][6];


        //求贴现因子
        for (int i=0;i<txl.length;i++){
            for (int j=0;j<math1.length;j++) {
                b[i][j] = 1 / Math.pow((txl[i] + 1), j);
                BigDecimal t = new BigDecimal(b[i][j]);
                //保留四位小数
                b[i][j] = t.setScale(4,BigDecimal.ROUND_HALF_UP).doubleValue();

            }
        }

        for(int j=0;j<2;j++){
            for(int i=0;i<6;i++){
                if(j==0){
                    System.out.println("第"+i+"年"+" 贴现率8%的贴现因子"+b[j][i]);
                }else{
                    System.out.println("第"+i+"年"+" 贴现率12%的贴现因子"+b[j][i]);
                }

            }
        }

        int[] project1result1=txz(math1,b);System.out.println("项目1贴现率8%的净现值:"+project1result1[0]+"  贴现率12%的净现值:"+project1result1[1]);
        int[] project1result2=txz(math2,b);System.out.println("项目2贴现率8%的净现值:"+project1result2[0]+"  贴现率12%的净现值:"+project1result2[1]);
        int[] project1result3=txz(math3,b);System.out.println("项目3贴现率8%的净现值:"+project1result3[0]+"  贴现率12%的净现值:"+project1result3[1]);
        int[] project1result4=txz(math4,b);System.out.println("项目4贴现率8%的净现值:"+project1result4[0]+"  贴现率12%的净现值:"+project1result4[1]);




    }

    static int[] txz(int[] a, double[][] b){
        int[] p=new int[2];
        for(int j=0;j<2;j++){
            int temp=0;
            for(int i=0;i<6;i++){
                temp=(int)(temp+a[i]*b[j][i]);
               // System.out.println(temp+"-----");
            }
            p[j]=temp;
        }
        return p;
    }

}

 

 运行结果示例: