(medium)LeetCode 227.Basic Calculator II

Implement a basic calculator to evaluate a simple expression string.

The expression string contains only non-negative integers, +-*/ operators and empty spaces . The integer division should truncate toward zero.

You may assume that the given expression is always valid.

Some examples:

"3+2*2" = 7
" 3/2 " = 1
" 3+5 / 2 " = 5

Note: Do not use the eval built-in library function.

代码如下:

public class Solution {
public int calculate(String s) {
int len;
if(s==null || (len=s.length())==0) return 0;
Stack<Integer> stack=new Stack<Integer>();
int num=0;
char sign='+';
for(int i=0;i<len;i++){
if(Character.isDigit(s.charAt(i))){
num=num*10+s.charAt(i)-'0';
}
if(!Character.isDigit(s.charAt(i)) && ' '!=s.charAt(i) || i==len-1){
if(sign=='-'){
stack.push(-num);
}
if(sign=='+'){
stack.push(num);
}
if(sign=='/'){
stack.push(stack.pop()/num);
}
if(sign=='*'){
stack.push(stack.pop()*num);
}
sign=s.charAt(i);
num=0;
}
}
int ret=0;
for(int i:stack){
ret+=i;
}
return ret;
}
}

运行结果:

(medium)LeetCode  227.Basic Calculator II

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