要求:编写一个脚本读入一些整数，分别输出这些整数中奇数的个数和偶数的个数，并输出0的个数.
实现脚本如下:
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#!/bin/bash#charpter_8-12declare -a arr2
echo "Please input some integer numbers seprated by SPACE:"
read -a arr2
counter_odd=0counter_even=0counter_0=0for i in "${arr2[@]}"
do if [[ i -ne 0 ]]
then
if [[ i%2 -eq 0 ]]
then
let counter_even+=1
else
let counter_odd+=1
fi
else
let counter_0+=1
fi
doneecho "偶数个数:$counter_even"
echo "奇数个数:$counter_odd"
echo "0的个数:$counter_0"
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脚本的执行效果:
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[root@localhost charpter8]# sh 8-12
Please input some integer numbers seprated by SPACE:10 11 0 12 13 0 14 15 0偶数个数:3奇数个数:30的个数:3[root@localhost charpter8]# sh 8-12
Please input some integer numbers seprated by SPACE:-12 -13 -14 0 12 13 14 15 0 17偶数个数:4奇数个数:40的个数:2[root@localhost charpter8]#
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可以看到准确的输出了结果.
本文转自 marbury 51CTO博客，原文链接:http://blog.51cto.com/magic3/1429696