将JSON的请求参数转化为C#可序列化对象！
JSON请求参数：
"{\"id\":1,"name":"张三","dept":"销售部"}"
或多组：
Json = "[{\"id\":1,"name":"张三","dept":"销售部"},{\"id\":2"name":"李四","dept":"销售部"}]"
首先要穷举可能用到的参数，或者每个请求单独写一个对象：
public class RequestParameters
{
/// <summary>
/// 应用范围：区域ID/部门ID/人员ID
/// </summary>
public string id { get; set; }
/// <summary>
/// 应用范围：姓名/区域名/部门名
/// </summary>
public string name { get; set; }
}
下面就是重点了，将字符串转化为实体对象
public T ToJson<T>(string json)
{
System.IO.MemoryStream stream2 = new System.IO.MemoryStream();
DataContractJsonSerializer ser2 = new DataContractJsonSerializer(typeof(T));
StreamWriter wr = new StreamWriter(stream2);
wr.Write(json);
wr.Flush();
stream2.Position = 0;
Object obj = ser2.ReadObject(stream2);
T param = (T)obj;
return param;
}
如果是返回一个List的话，就更简单了
public List<T> ToJson<T>(string json)
{
System.IO.MemoryStream stream2 = new System.IO.MemoryStream();
DataContractJsonSerializer ser2 = new DataContractJsonSerializer(typeof(List<T>));
StreamWriter wr = new StreamWriter(stream2);
wr.Write(json);
wr.Flush();
stream2.Position = 0;
Object obj = ser2.ReadObject(stream2);
List<T> params = (List<T>)obj;
return param;
}
就是这样，还有其他方法，比如使用正则表达式的：
private static void TestRegex18()
{
string jstring = "{\"112\":1,\"325\":2,\"109\":3}";
MatchCollection mc = Regex.Matches(jstring, @"""(?<key>[^""]+)"":(?<value>[^,}]+)");
Dictionary<string, string> dict = new Dictionary<string, string>();
foreach (Match m in mc)
{
if(dict.ContainsKey(m.Groups["key"].Value)) continue;//不能重复啊
dict.Add(m.Groups["key"].Value, m.Groups["value"].Value);
}
//dict
}