java中的stream的Map收集器操作

package test9;

import java.util.Collections;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
import java.util.function.Function;
import java.util.stream.Collectors;
import java.util.stream.Stream; public class CollectorsTest {
public static void main(String[] args) {
Map<String, Person> map = Stream
.of(Person.valueOf("小明", '男', 18), Person.valueOf("小丽", '女', 16), Person.valueOf("小王", '男', 19))
.collect(Collectors.toMap(Person::getName, Function.identity()));
System.out.println("map:" + map); Map<String, Person> map2 = Stream
.of(Person.valueOf("小明", '男', 18), Person.valueOf("小丽", '女', 16), Person.valueOf("小明", '男', 19))
.collect(Collectors.toMap(Person::getName, Function.identity(), (x, y) -> y));
System.out.println("如果有2个key重复了就用新的,‘y’,想用旧的代替就用'x',自己选择,map2:" + map2); /*
* 需求:要求将已有的国家名为key, 人名为value(当然也可以是对象)集合。
*/
Map<String, Set<String>> map3 = Stream
.of(Person.valueOf("China", "小明"), Person.valueOf("China", "小丽"), Person.valueOf("us", "Jack"),
Person.valueOf("us", "Alice"))
.collect(Collectors.toMap(Person::getCountry, p -> Collections.singleton(p.getName()), (x, y) -> {
Set<String> set = new HashSet<>(x);
set.addAll(y);
return set;
}));
System.out.println("map3:" + map3); // 将所有元素检查key不重复且最终包装成一个TreeMap对象
Map<String, String> map4 = Stream.of(Person.valueOf("China", "小明"), Person.valueOf("Chinsa", "小丽"), Person.valueOf("us", "Jack"),
Person.valueOf("uss", "Alice"))
.collect(Collectors.toMap(
Person::getCountry,
Person::getName, (x, y) ->
{
throw new IllegalStateException();
},TreeMap::new));
System.out.println(map4); }
} class Person {
private String country; private String name; private Character sex; private Integer age; public String getCountry() {
return country;
} public void setCountry(String country) {
this.country = country;
} public String getName() {
return name;
} public void setName(String name) {
this.name = name;
} public Character getSex() {
return sex;
} public void setSex(Character sex) {
this.sex = sex;
} public Integer getAge() {
return age;
} public void setAge(Integer age) {
this.age = age;
} @Override
public String toString() {
return "name:" + name + "sex:" + sex + "age" + age;
} public static Person valueOf(String country, String name) {
Person person = new Person();
person.country = country;
person.name = name;
return person;
} public static Person valueOf(String name, Character sex, Integer age) {
Person person = new Person();
person.name = name;
person.sex = sex;
person.age = age;
return person;
}
}

打印结果:

map:{小明=name:小明sex:男age18, 小丽=name:小丽sex:女age16, 小王=name:小王sex:男age19}

如果有2个key重复了就用新的,‘y’,想用旧的代替就用'x',自己选择,map2:{小明=name:小明sex:男age19, 小丽=name:小丽sex:女age16}

map3:{China=[小明, 小丽], us=[Alice, Jack]}

{China=小明, Chinsa=小丽, us=Jack, uss=Alice}

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